The inverse function of a function \( f(x) \) is denoted as \( f^{-1}(x) \) and satisfies the property: \[ f(f^{-1}(x)) = f^{-1}(f(x)) = x \]
In simpler terms, applying a function and then its inverse (or vice versa) will bring you back to the original input. For the inverse function to exist, the original function ( f(x) ) must be bijective—that is, both one-to-one (injective) and onto (surjective).
To have an inverse, a function must satisfy the condition that each input has a unique output and vice versa. Therefore, only one-to-one functions have inverses because they meet this requirement.
Why One-to-One inverse function?
If a function is not one-to-one, it doesn’t pass the horizontal line test, meaning some output values map to multiple input values. This ambiguity makes it impossible to define a single unique inverse
For example:
If \(f(x) = x^2\), both - 2 and 2 produces the same output, that is , \( f(-2) = f(2) = 4\)
Therefore, \(f^{-1}(4)\) would be both -2 and 2, which contradicts the definition of a function (each input must map to a unique output).
If 𝑓 is a one-to-one function, then 𝑓 has an inverse function \(f^{-1}\) such that:
for all \(x\) in the domain of \(f^{-1}\)
for all \(x\) in the domain of \(f\)
To graph an inverse function \(f^{-1}\), we can use the following techniques:
Example 1: Linear function
If \( f(x) = 2x + 3 \), solving for \( x \) in terms of \( y \): \[ y = 2x + 3 \quad \Rightarrow \quad x = \frac{y - 3}{2} \] So, the inverse function is \( f^{-1}(x) = \frac{x - 3}{2} \).
Example 2: Quadratic Function
Consider \( f(x) = x^2 \). This function is not one-to-one unless its domain is restricted \(e.g., ( x \geq 0 )\).